operator+,-,*,/ (std::complex)
来自cppreference.com
| (1) | ||
template< class T > std::complex<T> operator+( const std::complex<T>& lhs, const std::complex<T>& rhs ); |
(C++20 前) | |
template< class T > constexpr std::complex<T> operator+( const std::complex<T>& lhs, const std::complex<T>& rhs ); |
(C++20 起) | |
| (2) | ||
template< class T > std::complex<T> operator+( const std::complex<T>& lhs, const T& rhs ); |
(C++20 前) | |
template< class T > constexpr std::complex<T> operator+( const std::complex<T>& lhs, const T& rhs ); |
(C++20 起) | |
| (3) | ||
template< class T > std::complex<T> operator+( const T& lhs, const std::complex<T>& rhs ); |
(C++20 前) | |
template< class T > constexpr std::complex<T> operator+( const T& lhs, const std::complex<T>& rhs ); |
(C++20 起) | |
| (4) | ||
template< class T > std::complex<T> operator-( const std::complex<T>& lhs, const std::complex<T>& rhs ); |
(C++20 前) | |
template< class T > constexpr std::complex<T> operator-( const std::complex<T>& lhs, const std::complex<T>& rhs ); |
(C++20 起) | |
| (5) | ||
template< class T > std::complex<T> operator-( const std::complex<T>& lhs, const T& rhs ); |
(C++20 前) | |
template< class T > constexpr std::complex<T> operator-( const std::complex<T>& lhs, const T& rhs ); |
(C++20 起) | |
| (6) | ||
template< class T > std::complex<T> operator-( const T& lhs, const std::complex<T>& rhs ); |
(C++20 前) | |
template< class T > constexpr std::complex<T> operator-( const T& lhs, const std::complex<T>& rhs ); |
(C++20 起) | |
| (7) | ||
template< class T > std::complex<T> operator*( const std::complex<T>& lhs, const std::complex<T>& rhs ); |
(C++20 前) | |
template< class T > constexpr std::complex<T> operator*( const std::complex<T>& lhs, const std::complex<T>& rhs ); |
(C++20 起) | |
| (8) | ||
template< class T > std::complex<T> operator*( const std::complex<T>& lhs, const T& rhs ); |
(C++20 前) | |
template< class T > constexpr std::complex<T> operator*( const std::complex<T>& lhs, const T& rhs ); |
(C++20 起) | |
| (9) | ||
template< class T > std::complex<T> operator*( const T& lhs, const std::complex<T>& rhs ); |
(C++20 前) | |
template< class T > constexpr std::complex<T> operator*( const T& lhs, const std::complex<T>& rhs ); |
(C++20 起) | |
| (10) | ||
template< class T > std::complex<T> operator/( const std::complex<T>& lhs, const std::complex<T>& rhs ); |
(C++20 前) | |
template< class T > constexpr std::complex<T> operator/( const std::complex<T>& lhs, const std::complex<T>& rhs ); |
(C++20 起) | |
| (11) | ||
template< class T > std::complex<T> operator/( const std::complex<T>& lhs, const T& rhs ); |
(C++20 前) | |
template< class T > constexpr std::complex<T> operator/( const std::complex<T>& lhs, const T& rhs ); |
(C++20 起) | |
| (12) | ||
template< class T > std::complex<T> operator/( const T& lhs, const std::complex<T>& rhs ); |
(C++20 前) | |
template< class T > constexpr std::complex<T> operator/( const T& lhs, const std::complex<T>& rhs ); |
(C++20 起) | |
为复数算术和混合复数/标量算术实现二元运算符。将标量实参当做拥有等于实参的实部和设为零的虚部的复数。
1-3) 返回其实参的和
4-6) 返回从
lhs 减去 rhs 的结果7-9) 将实参相乘
10-12)
lhs 除以 rhs参数
| lhs, rhs | - | 实参:两个复数,或一个复数与一个拥有匹配类型(float、double、long double)的标量
|
返回值
1-3)
std::complex<T>(lhs) += rhs4-6)
std::complex<T>(lhs) -= rhs7-9)
std::complex<T>(lhs) *= rhs10-12)
std::complex<T>(lhs) /= rhs注解
模板实参推导不考虑隐式转换,故这些运算符不能用于整数/复数混合算术。所有情况下,标量必须与复数的底层类型拥有相同类型。
GCC 标志 "-fcx-limited-range"(包含于 "-ffast-math")更改复数乘/除的行为,移除浮点极端情况的检查。这会影响向量化。
示例
运行此代码
#include <complex>
#include <iostream>
int main()
{
std::complex<double> c2(2.0, 0.0);
std::complex<double> ci(0.0, 1.0);
std::cout << ci << " + " << c2 << " = " << ci + c2 << '\n'
<< ci << " * " << ci << " = " << ci * ci << '\n'
<< ci << " + " << c2 << " / " << ci << " = " << ci + c2 / ci << '\n'
<< 1 << " / " << ci << " = " << 1.0 / ci << '\n';
// std::cout << 1.f/ci; // 编译错误
// std::cout << 1/ci; // 编译错误
}
输出:
(0,1) + (2,0) = (2,1)
(0,1) * (0,1) = (-1,0)
(0,1) + (2,0) / (0,1) = (0,-1)
1 / (0,1) = (0,-1)
参阅
| 两个复数,或一个复数与一个标量的复合赋值 (公开成员函数) | |
| 对复数运用一元运算符 (函数模板) |