leetcode-2/code/lc160.java at master · xiaocy/leetcode-2

33 lines (33 loc) · 1.06 KB

package code;

* 160. Intersection of Two Linked Lists

* 题意：求两个链表的交叉点

* 难度：Easy

* 分类：LinkedList

* 思路：两种方法：1.找出两个链表的长度差x，长的先走x步； 2.走完一个链表，走另一个链表，两个cur都走了两个链表长度的和步

* Tips：两种方法的本质是一样的其实，都是找到了步数差，都遍历了两遍

public class lc160 {

public class ListNode {

int val;

ListNode next;

ListNode(int x) { val = x; }

}

public ListNode getIntersectionNode(ListNode headA, ListNode headB) {

if(headA==null||headB==null)

return null;

ListNode curA = headA;

ListNode curB = headB;

while (curA != curB) {

if(curA == null)

curA = headB;

if(curB == null)

curB = headA;

if(curA==curB)

return curA; //别忘了判断一下是否相等

curA = curA.next;

curB = curB.next;

}

return curA;

}

Navigation Menu