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8 changes: 8 additions & 0 deletions C/program-100/README.md
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Strong Numbers are the numbers whose sum of factorial of digits is equal to the original number.

Example -
Input : n = 145
Output : Yes
Sum of digit factorials = 1! + 4! + 5!
= 1 + 24 + 120
= 145
24 changes: 24 additions & 0 deletions C/program-100/strongNumber.c
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#include <stdio.h>

int main()
{
int n, f = 1, s = 0, r, i, n1;
scanf("%d", &n);
n = n1;
while (n)
{
r = n % 10; // Taking the last digit of the number
for (i = 1; i <= r; i++)
{
f = f * i;
}
s = s + f;
n /= 10;
}
if (s == n1)
printf("Strong no.");
else
printf("Not Strong no.");

return 0;
}
26 changes: 26 additions & 0 deletions C/program-64/ArmstrongNumber.c
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#include <stdio.h>
#include <math.h>
int main()
{
int number, originalNumber, remainder, result = 0, n = 0;
scanf("%d", &number);
originalNumber = number;

while (originalNumber != 0)
{
originalNumber /= 10;
++n;
}
originalNumber = number;
while (originalNumber != 0)
{
remainder = originalNumber % 10;
result += pow(remainder, n);
originalNumber /= 10;
}
if (result == number)
printf("yes");
else
printf("no");
return 0;
}
10 changes: 10 additions & 0 deletions C/program-64/README.md
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A positive integer of n digits is called an Armstrong number of order n (order is number of digits)

if -
abcd... = pow(a,n) + pow(b,n) + pow(c,n) + pow(d,n) + ....

Example -
Input : 153
Output : Yes
153 is an Armstrong number.
1*1*1 + 5*5*5 + 3*3*3 = 153
1 change: 1 addition & 0 deletions C/program-66/README.md
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Program to find fibonacci series upto n values in C language.
18 changes: 18 additions & 0 deletions C/program-66/fibonacciSeries.c
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#include <stdio.h>

int main()
{
int i, n, a = 0, b = 1, c;
printf("enter the no. of values = ");
scanf("%d", &n);
// Initiating the values as 0,1,...
printf("%d,%d,", a, b);
for (i = 1; i <= (n - 2); i++)
{
c = a + b; // creating the new value
printf("%d,", c);
a = b, b = c; // Updating the values
}

return 0;
}