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62 lines (50 loc) · 1.62 KB
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import java.util.*;
public class max_sum_subarray
{
/* Given an integer array nums, find the contiguous subarray (containing at least one number) which has the largest sum and return its sum.
A subarray is a contiguous part of an array.
Example 1:
Input: nums = [-2,1,-3,4,-1,2,1,-5,4]
Output: 6
Explanation: [4,-1,2,1] has the largest sum = 6.
*/
public static void main(String[] args)
{
Scanner sc = new Scanner(System.in);
System.out.print("Enter number of elements in the array: ");
int n = sc.nextInt();
System.out.print("Enter " + n + " array elements: ");
int[] a = new int[n];
for(int i=0; i<n; i++)
{
a[i] = sc.nextInt();
}
System.out.println("Maximum subarray sum using brute force method: " + brute_force(a));
System.out.println("Maximum subarray sum using Kadane's algorithm: " + kadane(a));
}
static int brute_force(int[] a) // Brute force algorithm with O(n*n) complexity
{
int max = Integer.MIN_VALUE, sum = 0;
for(int i=0; i<a.length; i++)
{
sum=0;
for(int j=0; j<a.length; j++)
{
sum += a[j];
max = Math.max(sum,max);
}
}
return max;
}
static int kadane(int[] a) // kadane's algorithm
{
int max = Integer.MIN_VALUE, sum = 0;
for(int i=0; i<a.length; i++)
{
sum += a[i];
max = Math.max(sum, max);
if(sum<0) sum=0;
}
return max;
}
}