#用python写一个程序，找出数组中差值为K的数共有几对 ##知乎上有人问“用python写一个程序，找出数组中差值为K的数共有几对” 如果你感觉黄哥的文章对你有帮助请打赏，支付宝账号：[email protected] [点击黄哥python培训试看视频播放地址](https://github.com/pythonpeixun/article/blob/master/python_shiping.md) [黄哥python远程视频培训班](https://github.com/pythonpeixun/article/blob/master/index.md) #coding:utf-8 """ 用python写一个程序，找出数组中差值为K的数共有几对 示例： 差值k=4 and 数组是[7, 6, 23,19,10,11, 9, 3, 15] 这样的结果是(7,11) (7,3) (6,10) (19,23) (15,19) (15,11) å…±6对 从标准输入读入两行数据 5 2 1 5 3 4 2 第一行代表Nå’ŒK, N是数组是一共有多少数字，K是所要求的差值 第二是数组，空白分格 输出到标准输出 Sample Input #00: 5 2 1 5 3 4 2 Sample Output #00: 3 Sample Input #01: 10 1 363374326 364147530 61825163 1073065718 1281246024 1399469912 428047635 491595254 879792181 1069262793 Sample Output #01: 0 """ def diff_of_element_list(lst, k): """黄哥python远程视频培训班 https://github.com/pythonpeixun/article/blob/master/index.md 黄哥python培训试看视频播放地址 https://github.com/pythonpeixun/article/blob/master/python_shiping.md """ newlst = [i + k for i in lst] return len(set(lst) & set(newlst)) if __name__ == '__main__': lst = [7, 6, 23,19,10,11, 9, 3, 15] k = 4 print(diff_of_element_list(lst, k)) lst = [1,5, 3, 4, 2] k = 2 print(diff_of_element_list(lst, k)) n, k = input("please input n and k:\n").split() lst = input("plesae input {0} number:\n".format(n)).split() lst = [int(i) for i in lst] print(diff_of_element_list(lst, int(k)))