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MAP_SHARED isn't proper for anonymous mappings for VxWorks #80829
anonymous mappings is not part of the POSIX standard, python user just need to specified -1 as fd value when do anonymous map, for example:
m=mmap.mmap(-1, 100)
then python adapter module(mmapmodule.c) try to specify MAP_SHARED or MAP_PRIVATE based on operate system requirement, Linux require MAP_SHARED, VxWorks require MAP_PRIVATE, this different should be hidden by this module, and python user won't be affected.
Currently, mmap is only adapted for the system which use MAP_SHARED when do anonymous map, VxWorks need be supported.
I don't understand why PR 12394 modifies flags afterwards, whereas "m = mmap.mmap(-1, 100)" doesn't specify explicitly flags. So the bug looks to be default flags set by Python, no?
>I don't understand why PR 12394 modifies flags afterwards, whereas "m = mmap.mmap(-1, 100)" doesn't specify explicitly flags. So the bug looks to be default flags set by Python, no?
Yes, this statement doesn't specify the flag, but as you said, the new_mmap_object() firstly set MAP_SHARED for flag, and in later code:
if (fd==-1) {
m_obj->fd=-1;
.....
#ifdefMAP_ANONYMOUS/* BSD way to map anonymous memory */flags |= MAP_ANONYMOUS;
#else
#endif
This routine will pass (MAP_ANONYMOUS | MAP_SHARED) to mmap and fd is -1, this is true for Linux, but for VxWorks, if fd is -1, the flag type should be (MAP_ANONYMOUS | MAP_PRIVATE), and this behavior is not part of the POSIX standard, we can't say VxWorks isn't right.
So my changes clear MAP_SHARED and set MAP_PRIVATE when the system type is VxWorks.
>Is MAP_SHARED constant available in C on VxWorks?
Yes, but for MAP_ANONYMOUS, it require set MAP_PRIVATE.
This PR still is try to enhance VxWorks support, doesn't affect Python user, and only change the behavior of VxWorks, other system don't have this issue, and also won't be influenced
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LihuaZhao commentedon Apr 17, 2019
anonymous mappings is not part of the POSIX standard, python user just need to specified -1 as fd value when do anonymous map, for example:
then python adapter module(mmapmodule.c) try to specify MAP_SHARED or MAP_PRIVATE based on operate system requirement, Linux require MAP_SHARED, VxWorks require MAP_PRIVATE, this different should be hidden by this module, and python user won't be affected.
Currently, mmap is only adapted for the system which use MAP_SHARED when do anonymous map, VxWorks need be supported.
https://en.wikipedia.org/wiki/Mmap
vstinner commentedon Apr 18, 2019
What is the current behavior of m = mmap.mmap(-1, 100)? Does it raise an exception?
vstinner commentedon Apr 18, 2019
I don't understand why PR 12394 modifies flags afterwards, whereas "m = mmap.mmap(-1, 100)" doesn't specify explicitly flags. So the bug looks to be default flags set by Python, no?
Is MAP_SHARED constant available in C on VxWorks?
Is mmap.MAP_SHARED constant available in Python on VxWorks?
LihuaZhao commentedon Apr 18, 2019
No, the following statement will return -1 without PR 12394
Yes, this statement doesn't specify the flag, but as you said, the new_mmap_object() firstly set MAP_SHARED for flag, and in later code:
#else
#endif
This routine will pass (MAP_ANONYMOUS | MAP_SHARED) to mmap and fd is -1, this is true for Linux, but for VxWorks, if fd is -1, the flag type should be (MAP_ANONYMOUS | MAP_PRIVATE), and this behavior is not part of the POSIX standard, we can't say VxWorks isn't right.
So my changes clear MAP_SHARED and set MAP_PRIVATE when the system type is VxWorks.
Yes, but for MAP_ANONYMOUS, it require set MAP_PRIVATE.
This PR still is try to enhance VxWorks support, doesn't affect Python user, and only change the behavior of VxWorks, other system don't have this issue, and also won't be influenced
vstinner commentedon May 21, 2019
New changeset 4fb1502 by Victor Stinner (Lihua Zhao) in branch 'master':
bpo-36648: fix mmap issue for VxWorks (GH-12394)
4fb1502