type Foo = {foo::Int}
bar :: Foo -> _
bar x = x + 1
Is it possible to use Foo instead of { foo :: Int} in error message?
It's much harder to understand the error especially with big records.
Could not match type
{ foo :: Int
}
with type
Int
while trying to match type { foo :: Int
}
with type Int
while checking that type { foo :: Int
}
is at least as general as type Int
while checking that type Int
is at least as general as type { foo :: Int
}
while checking that expression 1
has type { foo :: Int
}
while applying a function ((+) (#dict Semiring _1)) x
of type _1 -> _1
to argument 1
while inferring the type of ((+) x) 1
while checking that expression ((+) x) 1
has type _0
while checking that expression \x ->
((+) x) 1
has type { foo :: Int
}
-> _0
in value declaration bar
where _0 is an unknown type
_1 is an unknown type
Is it possible to use
Fooinstead of{ foo :: Int}in error message?It's much harder to understand the error especially with big records.