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| int idx = 0; //вспомогательный индех | ||
| for (int i = 0; i < b; ++i) { //проходим по всем корзинам | ||
| for (int j = 0; j < buckets[i][max]; ++j) { //проходим по всем элементам в корзине | ||
| while (arr[idx] % 2 > 0) idx++; //ищем в массиве индексы четных элементов, нечетные не трогаем |
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не дороговато кайлом бегать там, где ифа достаточно?
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homework 7