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FindNumbersWithSum.java
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59 lines (46 loc) · 1.47 KB
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package com.imood.msjava.offer;
import java.util.ArrayList;
/**
* @description: 剑指offer——题解(自解)
* @author: 微信公众号:码上Java
* @createDate: 2020/6/26/0026
* @version: 1.0
*/
public class FindNumbersWithSum {
/**
* 输入一个递增排序的数组和一个数字S,在数组中查找两个数,使得他们的和正好是S,
* 如果有多对数字的和等于S,输出两个数的乘积最小的。
*
* @param array
* @param sum
* @return
*/
public ArrayList<Integer> findNumbersWithSum(int[] array, int sum) {
ArrayList<Integer> result = new ArrayList<>();
if (array == null || array.length == 0) {
return result;
}
int low = 0;
int high = array.length - 1;
while (low < high) {
if (array[low] + array[high] == sum) {
result.add(array[low]);
result.add(array[high]);
return result;
} else if (array[low] + array[high] > sum) {
high--;
} else {
low++;
}
}
return result;
}
public static void main(String[] args) {
int[] array = {1, 2, 3, 4, 5, 6, 7, 8, 9};
int num = 7;
ArrayList<Integer> integers = new FindNumbersWithSum().findNumbersWithSum(array, num);
for (int i = 0; i < integers.size(); i++) {
System.out.print(integers.get(i) + " ");
}
}
}