To handle a conditional extension of null, shouldn't the regular case emit be updated to _this = _super !== null && _super.apply(this, arguments) || this, too?

@weswigham If you conditionally extend null you can't define a constructor since you can't be certain whether you need to call super. If you have an explicit super we don't emit the conditional _super !== null ... expression.

Actually, we just already do the right thing:

class Bar {
    constructor() {
        console.log("made");
    }
}

class Foo extends (Math.random() > 0.5 ? null : Bar) {
    x = 2
}

becomes

var Bar = /** @class */ (function () {
    function Bar() {
        console.log("made");
    }
    return Bar;
}());
var Foo = /** @class */ (function (_super) {
    __extends(Foo, _super);
    function Foo() {
        var _this = _super !== null && _super.apply(this, arguments) || this;
        _this.x = 2;
        return _this;
    }
    return Foo;
}((Math.random() > 0.5 ? null : Bar)));

Already covered.