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package leetcode.editor.cn;
//给你一个包含 n 个整数的数组 nums,判断 nums 中是否存在三个元素 a,b,c ,使得 a + b + c = 0 ?请你找出所有满足条件且不重复
//的三元组。
//
// 注意:答案中不可以包含重复的三元组。
//
//
//
// 示例:
//
// 给定数组 nums = [-1, 0, 1, 2, -1, -4],
//
//满足要求的三元组集合为:
//[
// [-1, 0, 1],
// [-1, -1, 2]
//]
//
// Related Topics 数组 双指针
// 👍 2817 👎 0
import java.util.ArrayList;
import java.util.Arrays;
import java.util.LinkedList;
import java.util.List;
public class P15ThreeSum {
public static void main(String[] args) {
Solution solution = new P15ThreeSum().new Solution();
int[] nums = new int[]{-1, 0, 1, 2, -1, -4};
solution.threeSum(nums);
// TO TEST
}
//leetcode submit region begin(Prohibit modification and deletion)
class Solution {
public List<List<Integer>> threeSum(int[] nums) {
if (nums.length == 0) {
return new ArrayList<>();
}
int target = 0;
Arrays.sort(nums);
List<List<Integer>> res = new LinkedList<>();
for (int i = 0; i < nums.length; i++) {
List<List<Integer>> result = twoSum(nums, i + 1, target - nums[i]);
for (List<Integer> list : result) {
list.add(nums[i]);
res.add(list);
}
while (i < (nums.length - 1) && nums[i + 1] == nums[i]) i++;
}
return res;
}
public List<List<Integer>> twoSum(int[] nums, int start, int target) {
int left = start, right = nums.length - 1;
List<List<Integer>> result = new LinkedList<>();
while (left < right) {
int sum = nums[left] + nums[right];
int leftNum = nums[left];
int rightNum = nums[right];
if (sum < target) {
while (left < right && leftNum == nums[left]) left++;
} else if (sum > target) {
while (left < right && rightNum == nums[right]) right--;
} else {
LinkedList<Integer> list = new LinkedList<>();
list.add(nums[left]);
list.add(nums[right]);
result.add(list);
while (left < right && leftNum == nums[left]) left++;
while (left < right && rightNum == nums[right]) right--;
}
}
return result;
}
}
//leetcode submit region end(Prohibit modification and deletion)
}