对列表内的元素进行排序，奇数在前，偶数在后。如果你高兴的话也可以反过来呀。 使用列表解析式解决！ ```python # -*- coding: utf-8 -*- from random import randrange def odd_even(seq): odd = [i for i in lst if i % 2 != 0] even = [i for i in lst if i % 2 == 0] return odd + even if __name__ == "__main__": lst = [randrange(100) for _ in range(10)] print(odd_even(lst)) ``` 什么，你想要奇偶数排好序的。行呀，导入之前自己写的插入排序！走起 ```python from random import randrange from insert_sort import * def odd_even(seq): odd = [i for i in lst if i % 2 != 0] odd = insert_sort(odd) even = [i for i in lst if i % 2 == 0] even = insert_sort(even) return odd + even if __name__ == "__main__": lst = [randrange(100) for _ in range(10)] print(odd_even(lst)) ```