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MIA // Eleyni & Claudia H // javascript-basic-algorithms #86

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MIA // Eleyni & Claudia H // javascript-basic-algorithms #86

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42 changes: 42 additions & 0 deletions claudiaheleyni.js
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Original file line number Diff line number Diff line change
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console.log("I'm Ready!");

var hacker1 = "Claudia"
console.log ("The drivers name is " + hacker1);

var hacker2 = "Eleyni"
console.log ("The navigators name is " + hacker2);

if (hacker1.length > hacker2.length) {
console.log ("The driver has the longest name, it has " + hacker1.length + " characters")

} else if (hacker2.length > hacker1.length) {
console.log ("Yo, navigator got the longest name, it has " + hacker2.length + " characters")
} else if (hacker1.length = hacker2.length) {
console.log ("wow, you both got equally long names " + hacker2.length + " characters!")
}

var driver = " "
for (var i = 0; i < hacker1.length; i++) {
driver += hacker1.toUpperCase()[i] + " ";
}

@sandrabosk sandrabosk Apr 3, 2018

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This works. The other way would be using JS methods:

for (var i = 0; i < 1; i++) {
  console.log(
    hacker1
      .split("")
      .join(" ")
      .toUpperCase()
  );
}

console.log(driver)

function reverse(str) {
return str.split('').reverse().join('');

}
reverse(hacker2);

@sandrabosk sandrabosk Apr 3, 2018

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Great!



var names = [hacker1, hacker2];
names.sort();
console.log(names);


if (names.indexOf(hacker1)===0){
console.log("The drivers name goes first")
} else if (names.indexOf(hacker2)===0){
console.log("Yo, tha navigator goes first definitely");
} else {
console.log("what?! you both got the same name?");
}

@sandrabosk sandrabosk Apr 3, 2018

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Try this way:

var n = hacker1.localeCompare(hacker2);
if (n === 1) {
  console.log("The driver's name goes first");
} else if (n === -1) {
  console.log("Yo, the navigator goes first definitely");
} else {
  console.log("What?! You both got the same name?");
}
console.log(n);

Google what .localeCompare() does and ask us if you have any questions.