/* For each multiple of 10 in the given array, change all the values * following it to be that multiple of 10, until encountering another * multiple of 10. So {2, 10, 3, 4, 20, 5} yields {2, 10, 10, 10, 20, 20}. */ public int[] tenRun(int[] nums) { int current; int i = 0; while(i < nums.length && nums[i] % 10 != 0) i++; if(i >= nums.length) return nums; current = nums[i]; i++; while(i < nums.length) { if(nums[i] % 10 == 0) current = nums[i]; else nums[i] = current; i++; } return nums; }