std::common_type<std::chrono::duration>
From cppreference.com
| Defined in header <chrono>
|
||
template< class Rep1, class Period1, class Rep2, class Period2 > struct common_type<std::chrono::duration<Rep1, Period1>, std::chrono::duration<Rep2, Period2>>; |
(since C++11) | |
Exposes the type named type, which is the common type of two std::chrono::durations, whose period is the greatest common divisor of Period1 and Period2.
Member types
| Member type | Definition |
type
|
std::chrono::duration<typename std::common_type<Rep1, Rep2>::type, /* see note */>
|
Note
The period of the resulting duration can be computed by forming a ratio of the greatest common divisor of Period1::num and Period2::num and the least common multiple of Period1::den and Period2::den.
Example
Run this code
#include <chrono>
#include <iostream>
#include <type_traits>
// std::chrono already finds the greatest common divisor,
// likely using std::common_type<>. We make the type
// deduction externally.
template<typename T,typename S>
constexpr auto durationDiff(const T& t, const S& s)
-> typename std::common_type<T,S>::type
{
typedef typename std::common_type<T,S>::type Common;
return Common(t) - Common(s);
}
int main()
{
using namespace std::literals;
constexpr auto ms = 30ms;
constexpr auto us = 1100us;
constexpr auto diff = durationDiff(ms, us);
std::cout << ms << " - " << us << " = " << diff << '\n';
}
Output:
30ms - 1100us = 28900us
See also
| specializes the std::common_type trait (class template specialization) | |
(C++11) |
determines the common type of a group of types (class template) |