/* Return the "centered" average of an array of ints, which we'll say is the * mean average of the values, except ignoring the largest and smallest * values in the array. If there are multiple copies of the smallest value, * ignore just one copy, and likewise for the largest value. Use int division * to produce the final average. You may assume that the array is length 3 * or more. */ public int centeredAverage(int[] nums) { int sum = 0; int min = nums[0]; int max = nums[0]; for(int i = 0; i < nums.length; i++) { sum += nums[i]; min = Math.min(min, nums[i]); max = Math.max(max, nums[i]); } return (sum - min - max) / (nums.length - 2); }