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patch-1
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algorithm
/
algorithm
/
src
/
level1
/
NumberOfHarshad.java
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52 lines (44 loc) · 1.62 KB
patch-1
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algorithm
/
algorithm
/
src
/
level1
/
NumberOfHarshad.java
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/*하샤드 수
문제 설명
양의 정수 x가 하샤드 수이려면 x의 자릿수의 합으로 x가 나누어져야 합니다. 예를 들어 18의 자릿수 합은 1+8=9이고, 18은 9로 나누어 떨어지므로 18은 하샤드 수입니다. 자연수 n을 입력받아 n이 하샤드 수인지 아닌지 검사하는 함수, solution을 완성해주세요.
제한 조건
n은 1 이상, 10000 이하인 정수입니다.
입출력 예
arr return
10 true
12 true
11 false
13 false
입출력 예 설명
입출력 예 #1
10의 모든 자릿수의 합은 1입니다. 10은 1로 나누어 떨어지므로 10은 하샤드 수입니다.
입출력 예 #2
12의 모든 자릿수의 합은 3입니다. 12는 3으로 나누어 떨어지므로 12는 하샤드 수입니다.
입출력 예 #3
11의 모든 자릿수의 합은 2입니다. 11은 2로 나누어 떨어지지 않으므로 11는 하샤드 수가 아닙니다.
입출력 예 #4
13의 모든 자릿수의 합은 4입니다. 13은 4로 나누어 떨어지지 않으므로 13은 하샤드 수가 아닙니다.*/
package
level1
;
public
class
NumberOfHarshad
{
public
static
void
main
(
String
[]
args
) {
// TODO Auto-generated method stub
NumberOfHarshad
noh
=
new
NumberOfHarshad
();
System
.
out
.
println
(
noh
.
SumDigit
(
18
));
}
public
boolean
solution
(
int
x
) {
boolean
answer
=
true
;
int
divider
=
this
.
SumDigit
(
x
);
answer
= (
x
%
divider
==
0
) ?
true
:
false
;
return
answer
;
}
public
int
SumDigit
(
int
n
) {
int
sum
=
0
;
String
s
=
String
.
valueOf
(
n
);
System
.
out
.
println
(
s
);
for
(
int
i
=
0
;
i
<
s
.
length
();
i
++) {
sum
+=
n
%
10
;
n
/=
10
;
}
return
sum
;
}
}
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