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algorithm
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algorithm
/
algorithm
/
src
/
level1
/
FindPrime.java
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57 lines (50 loc) · 1.35 KB
master
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algorithm
/
algorithm
/
src
/
level1
/
FindPrime.java
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/*소수 찾기
문제 설명
1부터 입력받은 숫자 n 사이에 있는 소수의 개수를 반환하는 함수, solution을 만들어 보세요.
소수는 1과 자기 자신으로만 나누어지는 수를 의미합니다.
(1은 소수가 아닙니다.)
제한 조건
n은 2이상 1000000이하의 자연수입니다.
입출력 예
n result
10 4
5 3
입출력 예 설명
입출력 예 #1
1부터 10 사이의 소수는 [2,3,5,7] 4개가 존재하므로 4를 반환
입출력 예 #2
1부터 5 사이의 소수는 [2,3,5] 3개가 존재하므로 3를 반환*/
package
level1
;
import
java
.
util
.
ArrayList
;
import
java
.
util
.
List
;
public
class
FindPrime
{
public
static
void
main
(
String
[]
args
) {
// TODO Auto-generated method stub
FindPrime
fp
=
new
FindPrime
();
System
.
out
.
println
(
fp
.
solution
(
10
));
}
public
int
solution
(
int
n
) {
int
answer
=
0
;
List
<
Boolean
>
primeList
=
new
ArrayList
<>();
primeList
.
add
(
false
);
primeList
.
add
(
false
);
int
nSqrt
= (
int
)
Math
.
sqrt
(
n
);
for
(
int
i
=
2
;
i
<=
n
;
i
++) {
primeList
.
add
(
i
,
true
);
}
for
(
int
i
=
2
;
i
<=
nSqrt
;
i
++) {
if
(!
primeList
.
get
(
i
)) {
continue
;
}
for
(
int
j
=
i
+
i
;
j
<=
n
;
j
+=
i
) {
primeList
.
set
(
j
,
false
);
}
}
for
(
int
i
=
0
;
i
<=
n
;
i
++) {
if
(
primeList
.
get
(
i
)) {
answer
++;
}
}
return
answer
;
}
}
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