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WaitNotifyTest.java
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65 lines (60 loc) · 2.52 KB
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package concurrent.notify;
/**
* @Auther: Jesper
* @Date: 2019/1/31 10:34
* @Description: 启动两个线程, 一个输出 1,3,5,7…99, 另一个输出 2,4,6,8…100 最后 STDOUT 中按序输出 1,2,3,4,5…100
*
* 用 Java 的 notify 机制实现
*/
public class WaitNotifyTest {
private static int state = 1; // 通状态值来实现两个线程交替打印
private static int num1 = 1; // 线程1 要打印的数值
private static int num2 = 2; // 线程2 要打印的数值
public static void main(String[] args) {
final WaitNotifyTest t = new WaitNotifyTest();
new Thread(new Runnable() {
@Override
public void run() {
while (num1 < 100) {
//两个线程都用t对象作为锁，保证每个交替期间只有一个线程在打印
synchronized (t) {
if (state != 1) {
try {
t.wait();
} catch (InterruptedException e) {
e.printStackTrace();
}
}
System.out.println(Thread.currentThread().getName() + ":" + num1);
num1 += 2; // 因为是交替打印，所以每次打印完，值需要+2
// 线程1打印完成后, 将state赋值为2, 表示接下来将轮到线程2打印
state = 2;
// notify()方法唤醒在t上wait的线程2, 同时线程1将退出同步代码块, 释放t锁
t.notify();
}
}
}
}).start();
new Thread(new Runnable() {
@Override
public void run() {
while (num2 < 100) {
//两个线程都用t对象作为锁，保证每个交替期间只有一个线程在打印
synchronized (t) {
if (state != 2) {
try {
t.wait();
} catch (InterruptedException e) {
e.printStackTrace();
}
}
System.out.println(Thread.currentThread().getName() + ":" + num2);
num2 += 2;
state = 1;
t.notify();
}
}
}
}).start();
}
}