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Copy pathLeftRotateString.cpp
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152 lines (120 loc) · 3.1 KB
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// 面试题58（二）：左旋转字符串
// 题目：字符串的左旋转操作是把字符串前面的若干个字符转移到字符串的尾部。
// 请定义一个函数实现字符串左旋转操作的功能。比如输入字符串"abcdefg"和数
// 字2，该函数将返回左旋转2位得到的结果"cdefgab"。
//要认真，不要搞错变量名！！！要弄清楚程序逻辑，以及参数的范围
#include <cstdio>
#include <string.h>
void Reverse(char *pBegin, char *pEnd)
{
if(pBegin == nullptr || pEnd == nullptr)
return;
while(pBegin < pEnd)
{
char temp = *pBegin;
*pBegin = *pEnd;
*pEnd = temp;
pBegin ++, pEnd --;
}
}
char* LeftRotateString(char* pStr, int n)
{
if(pStr != nullptr)
{
int nLength = static_cast<int>(strlen(pStr));
if(nLength > 0 && n > 0 && n < nLength)
{
char* pFirstStart = pStr;
char* pFirstEnd = pStr + n - 1;
char* pSecondStart = pStr + n;
char* pSecondEnd = pStr + nLength - 1;
// 翻转字符串的前面n个字符
Reverse(pFirstStart, pFirstEnd);
// 翻转字符串的后面部分
Reverse(pSecondStart, pSecondEnd);
// 翻转整个字符串
Reverse(pFirstStart, pSecondEnd);
}
}
return pStr;
}
char* LeftRotateString2(char* pStr, int n)
{
if(pStr != nullptr)
{
int nLength = static_cast<int>(strlen(pStr));
char str[nLength+1];
if(nLength > 0 && n > 0 && n < nLength)
{
for(int i=0;i<nLength-n;i++)
str[i]=pStr[n+i];
for(int i=nLength-n;i<nLength;i++)
str[i]=pStr[i-nLength+n];
printf("%s\n",str);
return str;
}
}
return pStr;
}
// ====================测试代码====================
void Test(const char* testName, char* input, int num, const char* expectedResult)
{
if(testName != nullptr)
printf("%s begins: ", testName);
char* result = LeftRotateString2(input, num);
if((input == nullptr && expectedResult == nullptr)
|| (input != nullptr && strcmp(result, expectedResult) == 0))
printf("Passed.\n\n");
else
printf("Failed.\n\n");
}
// 功能测试
void Test1()
{
char input[] = "abcdefg";
char expected[] = "cdefgab";
Test("Test1", input, 2, expected);
}
// 边界值测试
void Test2()
{
char input[] = "abcdefg";
char expected[] = "bcdefga";
Test("Test2", input, 1, expected);
}
// 边界值测试
void Test3()
{
char input[] = "abcdefg";
char expected[] = "gabcdef";
Test("Test3", input, 6, expected);
}
// 鲁棒性测试
void Test4()
{
Test("Test4", nullptr, 6, nullptr);
}
// 鲁棒性测试
void Test5()
{
char input[] = "abcdefg";
char expected[] = "abcdefg";
Test("Test5", input, 0, expected);
}
// 鲁棒性测试
void Test6()
{
char input[] = "abcdefg";
char expected[] = "abcdefg";
Test("Test6", input, 7, expected);
}
int main(int argc, char* argv[])
{
Test1();
Test2();
Test3();
Test4();
Test5();
Test6();
return 0;
}