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decodeString.lua
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163 lines (115 loc) · 4.01 KB
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#!/usr/local/bin/lua
local function printTable(t, level)
for k,v in pairs(t) do
if(type(v) == "table") then
printTable(v, level+10)
else
local space = ""
for i=1, level do
space = space.." "
end
print(space, k, v)
end
end
end
-- 先尝试构造最简单的, 没有空格
local simpleS = "{s010autosupply=10,s005reiki=1500}"
local simpleS2 = "{s010autosupply=10,s005reiki=1500,101={s008lordList={},s006skills={},s006wearid=0,s005level=1}}"
S = "{s010autosupply=1,s005reiki=1500,s006wearid=104,s004list={104={s008lordList={},s006skills={},s006wearid=0,s005level=1},101={s008lordList={},s006skills={},s006wearid=0,s005level=1},102={s008lordList={},s006skills={},s006wearid=102,s005level=1},103={s008lordList={},s006skills={},s006wearid=103,s005level=1}}}"
local sLen = 3
-- print(math.min(1,10,0.2))
local testTable = {}
local testSubTable = {}
testTable["AA"] = testSubTable
-- print(testTable)
-- 匹配N个数字
-- str = "10131dsg"
-- p = string.match(str, "%d+")
-- print(p, #p)
function DecodeSimple(simpleS)
local R = {}
local bracketNum = 0
local index = 1
local strLen = #simpleS
local bJudge = false
local curchar = ""
-- print(index, strLen)
while (index <= strLen)
do
local curchar = string.sub(simpleS, index, index)
if (curchar == "}") then
index = index + 1
elseif(bJudge == true) then
if (curchar == "s") then -- 如果是字符串作为属性名
local strNum = string.sub(simpleS, index+1, index + sLen)
local n = tonumber(strNum)
-- print("cur==s:", strNum, n)
index = index + sLen
local propName = string.sub(simpleS, index+1, index + n)
-- print("propName:", propName)
index = index + n + 1 -- 由于必然有=接着，因此还要+1
local followSubstr1 = string.sub(simpleS, index+1)
-- print("followSubstr1:", followSubstr1)
-- 查找=的后续子串的 , 或 } 作为取值的终止
local stopIndex = string.find(followSubstr1, string.match(followSubstr1, "[,}]") , 1)
local followValue = string.sub(followSubstr1, 1, stopIndex-1)
-- print("stopIndex:", stopIndex)
-- print("followValue:", followValue)
R[propName] = followValue
index = index + stopIndex
bJudge = true
else
-- 判断后续获得的第一个 数字串
local followSubstr2 = string.sub(simpleS, index)
local fProp = string.match(followSubstr2, "%d+")
R[fProp] = DecodeSimple(string.sub(simpleS, index + #fProp))
end
else
bJudge = false
if(curchar == "{") then
bracketNum = bracketNum + 1
bJudge = true
elseif(curchar == ",") then
bJudge = true
elseif(curchar == "}") then
-- 这种情况暂不考虑太复杂
bracketNum = bracketNum - 1
end
end
index = index + 1
print("")
end
-- print(bracketNum)
return R
end
-- R = DecodeSimple(simpleS)
R1 = DecodeSimple(simpleS2)
-- R2 = DecodeSimple(S)
-- printTable(R, 1)
printTable(R1, 1)
-- printTable(R2, 1)
-- 字符串找整数的方法
-- s = "Deadline is 30/05/1999, firm"
-- date = "%d%d/%d%d/%d%d%d%d"
-- print(string.sub(s, string.find(s, date))) --> 30/05/1999
-- 字符串转整数
-- print(tonumber("010210"))
function Decode(str)
local R = {}
local innerStrLen = 0
local bracketStack = {}
-- i = 0
-- while(i < 100)
-- do
-- print(i, #bracketRecord)
-- bracketRecord[#bracketRecord + 1] = i
-- i = i + 1
-- end
return R
end
-- Decode(S)
-- list[104] = {
-- lordList
-- }
function printTable(T)
end