Working with SQL
Surf to SQL Try Editor at W3Schools.com
Answer the following data queries. Keep track of the SQL you write by pasting it into this document under its appropriate header below. You will be submitting that through the regular fork, change, pull process.
Clicking the Restore Database button in the page will repopulate the database with the original data and discard all changes you have made.
SELECT *
FROM customers
WHERE country = "London"
SELECT *
FROM customers
WHERE postalcode = 1010
SELECT phone
FROM suppliers
WHERE supplierid = 11
SELECT *
FROM Orders
ORDER BY OrderDate DESC
find all suppliers who have names longer than 20 characters. You can use length(SupplierName) to get the length of the name. Returns 11 records.
SELECT *
FROM Suppliers
WHERE length(SupplierName) > 20
SELECT *
FROM Customers
WHERE CustomerName LIKE "%market%"
add a customer record for "The Shire", the contact name is "Bilbo Baggins" the address is "1 Hobbit-Hole" in "Bag End", postal code "111" and the country is "Middle Earth".
INSERT INTO customers(CustomerName, ContactName, Address, PostalCode, Country)
VALUES ("The Shire", "Bilbo Baggins", "1 Hobbit-Hole in Bag End", "111", "Middle Earth")
UPDATE customers
SET postalcode = "11122"
WHERE ContactName = "Bilbo Baggins"
list orders grouped by customer showing the number of orders per customer. Rattlesnake Canyon Grocery should have 7 orders.
SELECT c.customername as CustomerName, COUNT(o.customerid) as TotalOrders
FROM customers as c
INNER JOIN orders as o
ON c.customerid = o.customerid
GROUP BY c.customername
list customers names and the number of orders per customer. Sort the list by number of orders in descending order. Ernst Handel should be at the top with 10 orders followed by QUICK-Stop, Rattlesnake Canyon Grocery and Wartian Herkku with 7 orders each.
SELECT c.customername as CustomerName, COUNT(o.customerid) as TotalOrders
FROM customers as c
INNER JOIN orders as o
ON c.customerid = o.customerid
GROUP BY c.customername
ORDER BY COUNT(o.customerid) DESC
list orders grouped by customer's city showing number of orders per city. Returns 58 Records with Aachen showing 2 orders and Albuquerque showing 7 orders.
SELECT c.city as City, COUNT(o.customerid) as TotalOrders
FROM customers as c
INNER JOIN orders as o
ON c.customerid = o.customerid
GROUP BY c.city
delete all customers that have no orders. Should delete 17 (or 18 if you haven't deleted the record added) records.
DELETE FROM Customers
WHERE CustomerID NOT IN (SELECT CustomerID FROM Orders)
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use
SQLite Studioto create a database, name itbudget.sqlite3. -
add an
accountstable with the following schema:id, numeric value with no decimal places that should autoincrement.name, string, add whatever is necessary to make searching by name faster.budgetnumeric value.
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constraints
- the
idshould be the primary key for the table. - account
nameshould be unique. - account
budgetis required.
- the