A student that completes this project shows that they can:
- Query data from a single table
- Query data from multiple tables
- Create a new datadaase using PostgreSQL
Working with SQL
Surf to SQL Try Editor at W3Schools.com
Answer the following data queries. Keep track of the SQL you write by pasting it into this document under its appropriate header below. You will be submitting that through the regular fork, change, pull process.
Clicking the Restore Database button in the page will repopulate the database with the original data and discard all changes you have made.
SELECT * FROM customers WHERE city = 'London'
SELECT * FROM customers WHERE postalcode = 1010
SELECT phone FROM suppliers WHERE SupplierID = 11
SELECT orderdate FROM orders ORDER BY orderdate DESC
find all suppliers who have names longer than 20 characters. You can use length(SupplierName) to get the length of the name. Returns 11 records.
TSELECT * FROM suppliers WHERE length(suppliername)>20
SELECT * FROM customers WHERE customername like'%market%'
Don't forget the wildcard '%' symbols at the beginning and end of your substring to denote it can appear anywhere in the string in question
add a customer record for "The Shire", the contact name is "Bilbo Baggins" the address is "1 Hobbit-Hole" in "Bag End", postal code "111" and the country is "Middle Earth".
INSERT INTO CUSTOMERS (customername, contactname, address, postalcode, country) VALUES ('The Shire', 'Bilbo Baggins', '1 Hobbit-Hole in Bag end','111', 'Middle Earth')
UPDATE customers SET postalcode = 11122 WHERE contactname = 'Bilbo Baggins'
list orders grouped by customer showing the number of orders per customer. Rattlesnake Canyon Grocery should have 7 orders.
SELECT customername, COUNT(orderid) AS OrdersPerCustomer FROM orders o JOIN customers c ON o.customerid = c.customerid GROUP BY c.ContactName
There is more information about the COUNT clause on W3 Schools
list customers names and the number of orders per customer. Sort the list by number of orders in descending order. Ernst Handel should be at the top with 10 orders followed by QUICK-Stop, Rattlesnake Canyon Grocery and Wartian Herkku with 7 orders each.
SELECT customername, COUNT(orderid) AS OrdersPerCustomer FROM orders o JOIN customers c ON o.customerid = c.customerid GROUP BY c.ContactName ORDER BY OrdersPerCustomer DESC
list orders grouped by customer's city showing number of orders per city. Returns 58 Records with Aachen showing 2 orders and Albuquerque showing 7 orders.
SELECT c.city, COUNT(orderid) AS OrdersPerCity FROM orders o JOIN customers c ON o.customerid = c.customerid GROUP BY c.city ORDER BY OrdersPerCity DESC
delete all customers that have no orders. Should delete 17 (or 18 if you haven't deleted the record added) records.
This is done with a DELETE query
In the WHERE clause, you can provide another list with an IN keyword this list can be the result of another SELECT query. Write a query to return a list of CustomerIDs that meet the criteria above. Pass that to the IN keyword of the WHERE clause as the list of IDs to be deleted
Use a LEFT JOIN to join the Orders table onto the Customers table and check for a NULL value in the OrderID column
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use pgAdmin to create a database, naming it
budget. -
add an
accountstable with the following schema:id, numeric value with no decimal places that should autoincrement.name, string, add whatever is necessary to make searching by name faster.budgetnumeric value.
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constraints
- the
idshould be the primary key for the table. - account
nameshould be unique. - account
budgetis required.
- the