package MethodOverloading; public class NullTest1 { /* * If more than one member method is both accessible and applicable to a method invocation, * it is necessary to choose one to provide the descriptor for the run-time method dispatch. * * The Java programming language uses the rule that the most specific method is chosen. * */ public static void method(Object obj){ System.out.println("method with param type - Object"); } public static void method(String obj){ System.out.println("method with param type - String"); } // public static void method(StringBuffer strBuf){ // System.out.println("method with param type - StringBuffer"); // } /* * Why is the compiler not able to pick 'the most specific' here - because both "String" and "StringBuffer" are are sub-classes. of the Object class, but without being in the same inheritance hierarchy. For finding 'the most specific' method, the compiler needs to find a method having the parameter type, which is a sub-class of the parameter types of all other overloaded methods. * */ public static void main(String [] args){ method(null); } }