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5章の練習問題 (traP-jp#9)
* add practices * edit config.ts * "+=" is difficulty to pronounce * bits is not allowed * add practice "exponentation" * fix 日本語 * delete practice "Exponantation" * add hint to divide-each-diff * line-numbers * deleted exponentation from index.md
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‎docs/.vitepress/config.ts‎

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{ text: '引数', link: '/text/chapter-5/argument' },
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{ text: '返り値', link: '/text/chapter-5/return-value' },
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{ text: '参照渡し', link: '/text/chapter-5/call-by-ref' },
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{text: '練習問題', link: '/text/chapter-5/practice/'}
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]
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},
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{

‎docs/text/chapter-5/practice/divide-each-difficulty.md‎

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# Divide each difficulty
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以下の$n \leq 7$を受け取って$n \times n$の行列$a_{i,j}=Fibonatti_{ij}$を出力するプログラムの、フィボナッチ数列の解を求める部分を別の関数`int fibonatti(int index);`に分離してみよう。
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```cpp:line-numbers
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#include <iostream>
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using namespace std;
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int main() {
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int n;
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cin >> n;
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for (int i = 0; i < n; i++) {
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for (int j = 0; j < n; j++) {
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// ここから下を関数に切り分ける
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// print (i*j)th of fibonatti sequence
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int first = 1, second = 1;
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for (int k = 0; k < i*j; k++) {
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int next = first + second;
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first = second;
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second = next;
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}
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// ここから上を関数に切り分ける
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cout << second << " ";
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}
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cout << endl;
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}
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}
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```
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::: spoiler Hint
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下のコードの`// ここにフィボナッチ数列の計算を実装しよう`の部分を実装してみよう。
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```cpp:line-numbers
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#include <iostream>
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using namespace std;
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int fibonatti(int index) {
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int first = 1, second = 1;
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// ここにフィボナッチ数列の計算を実装しよう
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return second;
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}
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int main() {
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int n;
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cin >> n;
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for (i = 0; i < n; i++) {
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for (j = 0; j < n; j++) {
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int fib_ij = fibonatti(i*j);
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cout << fib_ij << " ";
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}
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cout << endl;
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}
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}
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```
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:::
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::: spoiler Answer
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```cpp:line-numbers
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#include <iostream>
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using namespace std;
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int fibonatti(int index) {
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int first = 1, second = 1;
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for (k = 0; k < index; k++) {
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int next = first + second;
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first = second;
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second = next;
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}
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return second;
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}
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int main() {
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int n;
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cin >> n;
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for (i = 0; i < n; i++) {
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for (j = 0; j < n; j++) {
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int fib_ij = fibonatti(i*j);
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cout << fib_ij << " ";
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}
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cout << endl;
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}
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}
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```
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:::

‎docs/text/chapter-5/practice/index.md‎

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# 練習問題 - Chapter 5
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- [Divide each difficulty](divide-each-difficulty)
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- [Operator+=](plus-equal)

‎docs/text/chapter-5/practice/plus-equal.md‎

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# Operator+=
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`int`型の`a`と`b`について`a`に`b`を足す操作である
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```cpp
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a += b;
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```
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で用いる`+=`演算子と同じ働きをする関数を書こう。
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::: spoiler Hint 1
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`a`を参照渡しで受け取ることで、`a`の値を書き換えることができる。
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:::
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::: spoiler Answer
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```cpp:line-numbers
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void compound_assigned_plus(int& lhs, int rhs) {
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lhs = lhs + rhs;
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return;
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}
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```
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:::

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