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string_util.py
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57 lines (43 loc) · 1.58 KB
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# Copyright 2018-2021 Streamlit Inc.
#
# Licensed under the Apache License, Version 2.0 (the "License");
# you may not use this file except in compliance with the License.
# You may obtain a copy of the License at
#
# http://www.apache.org/licenses/LICENSE-2.0
#
# Unless required by applicable law or agreed to in writing, software
# distributed under the License is distributed on an "AS IS" BASIS,
# WITHOUT WARRANTIES OR CONDITIONS OF ANY KIND, either express or implied.
# See the License for the specific language governing permissions and
# limitations under the License.
import textwrap
def decode_ascii(string):
"""Decodes a string as ascii."""
return string.decode("ascii")
def clean_text(text):
return textwrap.dedent(str(text)).strip()
def escape_markdown(raw_string):
"""Returns a new string which escapes all markdown metacharacters.
Args
----
raw_string : str
A string, possibly with markdown metacharacters, e.g. "1 * 2"
Returns
-------
A string with all metacharacters escaped.
Examples
--------
::
escape_markdown("1 * 2") -> "1 \\* 2"
"""
metacharacters = ["\\", "*", "-", "=", "`", "!", "#", "|"]
result = raw_string
for character in metacharacters:
result = result.replace(character, "\\" + character)
return result
TEXTCHARS = bytearray({7, 8, 9, 10, 12, 13, 27} | set(range(0x20, 0x100)) - {0x7F})
def is_binary_string(inp):
"""Guess if an input bytesarray can be encoded as a string."""
# From https://stackoverflow.com/a/7392391
return bool(inp.translate(None, TEXTCHARS))