字符串压缩 #27

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1. CodeRookie262

   added

   算法

   on Jan 21, 2021
2. CodeRookie262 commented on Jan 22, 2021

   

   CodeRookie262

   on Jan 22, 2021

   OwnerAuthor

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   var compressString = function(S) {
       let ans = '',
           s = S[0],
           sort = 1;
           for(var i = 1,l = S.length;i < l;i++){
               if(s === S[i]) {
                   sort++
               }else{
                   ans = ans + s + sort;
                   s = S[i];
                   sort = 1 
               }
           }
           ans = ans + s + sort;
           return S.length <= ans.length ? S : ans
   };