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53 lines (33 loc) · 1.04 KB
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import re
# match 只会在开始进行查询
# search 整个字符串查询
# group 匹配正则表达式中（num）的内容 group(0)为整个正则表达式 group（1，2）指定多个分组 groups（）拿出所有子分组
text = " Apple's price $99 , orange's price is $10 . "
ret = re.search("\.*(\$\d+).*(\$\d+)",text)
print(ret.group(1,2))
for i in range(1,3):
if i % 2 != 0 :
resp = ret[i]+ret[i+1]
print(resp)
#findall
# text = " Apple's price $99 , orange's price is $10 . "
# ret = re.findall('\$\d+',text)
# print(ret)
#sub替换
#text = " Apple's price $99 , orange's price is $10 . "
# ret = re.sub('\$\d+',"不要钱",text)
# print(ret)
# split分割
# text = " Apple's price $99 , orange's price is $10 . "
# # ret = re.split(' |,',text)
# ret = re.split('[^a-z]',text)
# print(ret)
#compile
# text = 'the number is 20.50'
# r = re.compile(r"""
# \d+ #小数点前的数字
# \.? #小数点
# \d* #小数点后面的数字
# """,re.VERBOSE)
# ret = re.search(r,text)
# print(ret.group)