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Dzhoker1
reviewed
Mar 30, 2020
| for i in range(len(string)): | ||
| for j in range(i + 1, len(string) if i == 0 else len(string) + 1): | ||
| bar.append(hashlib.sha1(string[i:j].encode('utf-8')).hexdigest()) | ||
| return len(set(bar)) |
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А если сразу использовать set не нужно будет тратить память на list. Даже не сохранив множество в переменную вы тратите память на его формирование.
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