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BestWeekOfZen
studyAlgorithm
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master
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studyAlgorithm
/
problem
/
maxPathSum_test.go
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37 lines (32 loc) · 1.32 KB
master
Breadcrumbs
studyAlgorithm
/
problem
/
maxPathSum_test.go
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package
problem
import
"math"
var
ans
int
/**
124 给定一个非空二叉树,返回其最大路径和。
本题中,路径被定义为一条从树中任意节点出发,达到任意节点的序列。该路径至少包含一个节点,且不一定经过根节点。
问题分析:
1.这道题就是一个经典的深度递归问题,树肯定是要递归了,深度或者广度
2.因为我们要求的就是最大路径,所以我们肯定要进行深度的遍历
3.我总结了一些我关于深度递归问题的解法,总结为一句话
思路要正向,执行要逆向
4.思路正向就是说,我们假设递归内的递归经完成,在这个例子里,我们就假设左右节点返回的就是
他们的最优解,我们的情况就分为了两种:
经过当前节点的左右节点
经过当前节点的左右节点中较大的一个
这样我们就覆盖了所有的情况,递归方法如下代码
*/
func
maxPathSum
(
root
*
TreeNode
)
int
{
ans
=
INT32_MIN
dfsMax
(
root
)
return
ans
}
func
dfsMax
(
node
*
TreeNode
)
int
{
if
node
==
nil
{
return
0
}
left
:=
int
(
math
.
Max
(
float64
(
dfsMax
(
node
.
Left
)),
0
))
right
:=
int
(
math
.
Max
(
float64
(
dfsMax
(
node
.
Right
)),
0
))
newPath
:=
node
.
Val
+
left
+
right
ans
=
int
(
math
.
Max
(
float64
(
newPath
),
float64
(
ans
)))
return
node
.
Val
+
int
(
math
.
Max
(
float64
(
left
),
float64
(
right
)))
}
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