std::set_symmetric_difference
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<metanoindex/>
<tbody> </tbody>| Déclaré dans l'en-tête <algorithm>
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template< class InputIt1, class InputIt2, class OutputIt > OutputIt set_symmetric_difference( InputIt1 first1, InputIt1 last1, InputIt2 first2, InputIt2 last2, OutputIt d_first ); |
(1) | |
template< class InputIt1, class InputIt2, class OutputIt, class Compare > OutputIt set_symmetric_difference( InputIt1 first1, InputIt1 last1, InputIt2 first2, InputIt2 last2, OutputIt d_first, Compare comp ); |
(2) | |
Copie les éléments de la gamme
[first1, last1) triés qui ne se trouvent pas dans la gamme [first2, last2) triés et les éléments de la gamme [first2, last2) triés qui ne se trouvent pas dans la gamme [first1, last1) triés au début plage à d_first. La plage résultante est également triée. La première version prévoit à la fois d'entrée se situe à trier avec operator<, la deuxième version s'attend à ce qu'ils soient triés à la comp fonction de comparaison donnée. Si un élément est trouvé m fois en [first1, last1) et n fois dans [first2, last2), il sera copié dans d_first exactement std::abs(m-n) fois. Si m>n, le m-n dernier de ces éléments sont copiés à partir [first1,last1), sinon les éléments n-m derniers sont copiés à partir [first2,last2). La gamme résultante ne peut pas faire double emploi avec l'une des plages d'entrée .Original:
Copies the elements from the sorted range
[first1, last1) which are not found in the sorted range [first2, last2) and the elements from the sorted range [first2, last2) which are not found in the sorted range [first1, last1) to the range beginning at d_first. The resulting range is also sorted. The first version expects both input ranges to be sorted with operator<, the second version expects them to be sorted with the given comparison function comp. If some element is found m times in [first1, last1) and n times in [first2, last2), it will be copied to d_first exactly std::abs(m-n) times. If m>n, then the last m-n of those elements are copied from [first1,last1), otherwise the last n-m elements are copied from [first2,last2). The resulting range cannot overlap with either of the input ranges.The text has been machine-translated via Google Translate.
You can help to correct and verify the translation. Click here for instructions.
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Paramètres
| first1, last1 | - | la première gamme d'éléments triés
Original: the first sorted range of elements The text has been machine-translated via Google Translate. You can help to correct and verify the translation. Click here for instructions. |
| first2, last2 | - | la seconde plage d'éléments triés
Original: the second sorted range of elements The text has been machine-translated via Google Translate. You can help to correct and verify the translation. Click here for instructions. |
| comp | - | comparison function which returns true if the first argument is less than the second. The signature of the comparison function should be equivalent to the following:
The signature does not need to have |
| Type requirements | ||
-InputIt1 must meet the requirements of InputIterator.
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-InputIt2 must meet the requirements of InputIterator.
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-OutputIt must meet the requirements of OutputIterator.
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Retourne la valeur
Iterator-delà de la fin de la gamme construit .
Original:
Iterator past the end of the constructed range.
The text has been machine-translated via Google Translate.
You can help to correct and verify the translation. Click here for instructions.
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Complexité
A comparaisons plupart 2·(N1+N2-1), où N1
= std::distance(first1, last1) et N2 = std::distance(first2, last2) .Original:
At most 2·(N1+N2-1) comparisons, where N1
= std::distance(first1, last1) and N2 = std::distance(first2, last2).The text has been machine-translated via Google Translate.
You can help to correct and verify the translation. Click here for instructions.
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Mise en œuvre possible
| First version |
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template<class InputIt1, class InputIt2, class OutputIt>
OutputIt set_difference(InputIt1 first1, InputIt1 last1,
InputIt2 first2, InputIt2 last2,
OutputIt d_first)
{
while (first1 != last1) {
if (first2 == last2) return std::copy(first1, last1, d_first);
if (*first1 < *first2) {
*d_first++ = *first1++;
} else {
if (*first2 < *first1) {
*d_first++ = *first2;
} else {
++first1;
}
++first2;
}
}
return std::copy(first2, last2, d_first);
}
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| Second version |
template<class InputIt1, class InputIt2,
class OutputIt, class Compare>
OutputIt set_difference(InputIt1 first1, InputIt1 last1,
InputIt2 first2, InputIt2 last2,
OutputIt d_first, Compare comp)
{
while (first1 != last1) {
if (first2 == last2) return std::copy(first1, last1, d_first);
if (comp(*first1, *first2)) {
*d_first++ = *first1++;
} else {
if (comp(*first2, *first1)) {
*d_first++ = *first2;
} else {
++first1;
}
++first2;
}
}
return std::copy(first2, last2, d_first);
}
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Exemple
#include <iostream>
#include <vector>
#include <algorithm>
#include <iterator>
int main()
{
std::vector<int> v1{1,2,3,4,5,6,7,8 };
std::vector<int> v2{ 5, 7, 9,10};
std::sort(v1.begin(), v1.end());
std::sort(v2.begin(), v2.end());
std::vector<int> v_intersection;
std::set_symmetric_difference(
v1.begin(), v1.end(),
v2.begin(), v2.end(),
std::back_inserter(v_intersection));
for(int n : v_intersection)
std::cout << n << ' ';
}
Résultat :
1 2 3 4 6 8 9 10
Voir aussi
retourne vrai si un ensemble est un sous-ensemble de l'autre Original: returns true if one set is a subset of another The text has been machine-translated via Google Translate. You can help to correct and verify the translation. Click here for instructions. (fonction générique) | |
calcule la différence entre deux ensembles Original: computes the difference between two sets The text has been machine-translated via Google Translate. You can help to correct and verify the translation. Click here for instructions. (fonction générique) | |
calcule l'union de deux ensembles Original: computes the union of two sets The text has been machine-translated via Google Translate. You can help to correct and verify the translation. Click here for instructions. (fonction générique) | |
calcule l'intersection des deux ensembles Original: computes the intersection of two sets The text has been machine-translated via Google Translate. You can help to correct and verify the translation. Click here for instructions. (fonction générique) | |