std::lexicographical_compare
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<tbody> </tbody>| Déclaré dans l'en-tête <algorithm>
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template< class InputIt1, class InputIt2 > bool lexicographical_compare( InputIt1 first1, InputIt1 last1, InputIt2 first2, InputIt2 last2 ); |
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template< class InputIt1, class InputIt2, class Compare > bool lexicographical_compare( InputIt1 first1, InputIt1 last1, InputIt2 first2, InputIt2 last2, Compare comp ); |
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Vérifie si le
[first1, last1) première gamme est lexicographiquement moins que le [first2, last2) seconde plage. La première version utilise operator< de comparer les éléments, la deuxième version utilise la fonction de comparaison donnée comp .Original:
Checks if the first range
[first1, last1) is lexicographically less than the second range [first2, last2). The first version uses operator< to compare the elements, the second version uses the given comparison function comp.The text has been machine-translated via Google Translate.
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Comparaison lexicographique est une opération ayant les propriétés suivantes:
Original:
Lexicographical comparison is a operation with the following properties:
The text has been machine-translated via Google Translate.
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- Deux gammes sont comparées élément par élément .Original:Two ranges are compared element by element.The text has been machine-translated via Google Translate.
You can help to correct and verify the translation. Click here for instructions. - L'élément non-concordance première définit ce qui est lexicographiquement gamme moins ou' plus que l'autre .Original:The first mismatching element defines which range is lexicographically less or greater than the other.The text has been machine-translated via Google Translate.
You can help to correct and verify the translation. Click here for instructions. - Si une plage est un préfixe d'un autre, plus courte portée est lexicographiquement moins que l'autre .Original:If one range is a prefix of another, the shorter range is lexicographically less than the other.The text has been machine-translated via Google Translate.
You can help to correct and verify the translation. Click here for instructions. - Si deux gammes présentent des éléments équivalents et sont de la même longueur, puis les intervalles sont égaux' lexicographiquement .Original:If two ranges have equivalent elements and are of the same length, then the ranges are lexicographically equal.The text has been machine-translated via Google Translate.
You can help to correct and verify the translation. Click here for instructions. - Une plage vide est lexicographiquement moins que tout autre domaine non vide .Original:An empty range is lexicographically less than any non-empty range.The text has been machine-translated via Google Translate.
You can help to correct and verify the translation. Click here for instructions. - Deux plages vides sont lexicographiquement' égalité .Original:Two empty ranges are lexicographically equal.The text has been machine-translated via Google Translate.
You can help to correct and verify the translation. Click here for instructions.
Paramètres
| first1, last1 | - | la première gamme d'éléments à examiner
Original: the first range of elements to examine The text has been machine-translated via Google Translate. You can help to correct and verify the translation. Click here for instructions. |
| first2, last2 | - | la seconde plage d'éléments à examiner
Original: the second range of elements to examine The text has been machine-translated via Google Translate. You can help to correct and verify the translation. Click here for instructions. |
| comp | - | comparison function which returns true if the first argument is less than the second. The signature of the comparison function should be equivalent to the following:
The signature does not need to have |
| Type requirements | ||
-InputIt1, InputIt2 must meet the requirements of InputIterator.
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Retourne la valeur
true si la première gamme est lexicographiquement moins que le second .Original:
true if the first range is lexicographically less than the second.The text has been machine-translated via Google Translate.
You can help to correct and verify the translation. Click here for instructions.
You can help to correct and verify the translation. Click here for instructions.
Complexité
À la plupart des applications 2·min(N1, N2) de l'opération de comparaison, où
N1 = std::distance(first1, last1) et N2 = std::distance(first2, last2) .Original:
At most 2·min(N1, N2) applications of the comparison operation, where
N1 = std::distance(first1, last1) and N2 = std::distance(first2, last2).The text has been machine-translated via Google Translate.
You can help to correct and verify the translation. Click here for instructions.
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Mise en œuvre possible
| First version |
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template<class InputIt1, class InputIt2>
bool lexicographical_compare(InputIt1 first1, InputIt1 last1,
InputIt2 first2, InputIt2 last2)
{
for ( ; (first1 != last1) && (first2 != last2); first1++, first2++ ) {
if (*first1 < *first2) return true;
if (*first2 < *first1) return false;
}
return (first1 == last1) && (first2 != last2);
}
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| Second version |
template<class InputIt1, class InputIt2, class Compare>
bool lexicographical_compare(InputIt1 first1, InputIt1 last1,
InputIt2 first2, InputIt2 last2,
Compare comp)
{
for ( ; (first1 != last1) && (first2 != last2); first1++, first2++ ) {
if (comp(*first1, *first2)) return true;
if (comp(*first2, *first1)) return false;
}
return (first1 == last1) && (first2 != last2);
}
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Exemple
#include <algorithm>
#include <iostream>
#include <vector>
#include <cstdlib>
#include <ctime>
int main()
{
std::vector<char> v1 {'a', 'b', 'c', 'd'};
std::vector<char> v2 {'a', 'b', 'c', 'd'};
std::srand(std::time(0));
while (!std::lexicographical_compare(v1.begin(), v1.end(),
v2.begin(), v2.end())) {
for (auto c : v1) std::cout << c << ' ';
std::cout << ">= ";
for (auto c : v2) std::cout << c << ' ';
std::cout << '\n';
std::random_shuffle(v1.begin(), v1.end());
std::random_shuffle(v2.begin(), v2.end());
}
for (auto c : v1) std::cout << c << ' ';
std::cout << "< ";
for (auto c : v2) std::cout << c << ' ';
std::cout << '\n';
}
Résultat possible :
a b c d >= a b c d
d a b c >= c b d a
b d a c >= a d c b
a c d b < c d a b