std::remove_reference
From cppreference.com
| Defined in header <type_traits>
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template< class T > struct remove_reference; |
(since C++11) | |
If the type T is a reference type, provides the member typedef type which is the type referred to by T. Otherwise type is T.
If the program adds specializations for std::remove_reference, the behavior is undefined.
Member types
| Name | Definition |
type
|
the type referred by T or T if it is not a reference
|
Helper types
template< class T > using remove_reference_t = typename remove_reference<T>::type; |
(since C++14) | |
Possible implementation
template<class T> struct remove_reference { typedef T type; };
template<class T> struct remove_reference<T&> { typedef T type; };
template<class T> struct remove_reference<T&&> { typedef T type; };
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Example
Run this code
#include <iostream>
#include <type_traits>
int main()
{
std::cout << std::boolalpha;
std::cout << "std::remove_reference<int>::type is int? "
<< std::is_same<int, std::remove_reference<int>::type>::value << '\n';
std::cout << "std::remove_reference<int&>::type is int? "
<< std::is_same<int, std::remove_reference<int&>::type>::value << '\n';
std::cout << "std::remove_reference<int&&>::type is int? "
<< std::is_same<int, std::remove_reference<int&&>::type>::value << '\n';
std::cout << "std::remove_reference<const int&>::type is const int? "
<< std::is_same<const int,
std::remove_reference<const int&>::type>::value << '\n';
}
Output:
std::remove_reference<int>::type is int? true
std::remove_reference<int&>::type is int? true
std::remove_reference<int&&>::type is int? true
std::remove_reference<const int&>::type is const int? true
See also
(C++11) |
checks if a type is either an lvalue reference or rvalue reference (class template) |
(C++11)(C++11) |
adds an lvalue or rvalue reference to the given type (class template) |
(C++20) |
combines std::remove_cv and std::remove_reference (class template) |