std::add_lvalue_reference, std::add_rvalue_reference
From cppreference.com
| Defined in header <type_traits>
|
||
template< class T > struct add_lvalue_reference; |
(1) | (since C++11) |
template< class T > struct add_rvalue_reference; |
(2) | (since C++11) |
Creates an lvalue or rvalue reference type of T.
| Type trait | The type referred by the nested type type
| |
|---|---|---|
T is a referenceable type
|
T is not a referenceable type
| |
| (1) | T&[1]
|
T
|
| (2) | T&&[2]
| |
- ↑ This rule reflects the semantics of reference collapsing.
- ↑ This rule reflects the semantics of reference collapsing. Note that
std::add_rvalue_reference<T&>::typeisT&, which is not an rvalue reference type.
If the program adds specializations for any of the templates described on this page, the behavior is undefined.
Nested types
| Name | Definition |
type
|
determined as above |
Helper types
template< class T > using add_lvalue_reference_t = typename add_lvalue_reference<T>::type; |
(since C++14) | |
template< class T > using add_rvalue_reference_t = typename add_rvalue_reference<T>::type; |
(since C++14) | |
Notes
The major difference to directly using T& or T&& is that T can be a non-referenceable type. For example, std::add_lvalue_reference<void>::type is void, while void& leads to a compilation error.
Possible implementation
namespace detail
{
template<class T>
struct type_identity { using type = T; }; // or use std::type_identity (since C++20)
template<class T> // Note that “cv void&” is a substitution failure
auto try_add_lvalue_reference(int) -> type_identity<T&>;
template<class T> // Handle T = cv void case
auto try_add_lvalue_reference(...) -> type_identity<T>;
template<class T>
auto try_add_rvalue_reference(int) -> type_identity<T&&>;
template<class T>
auto try_add_rvalue_reference(...) -> type_identity<T>;
} // namespace detail
template<class T>
struct add_lvalue_reference
: decltype(detail::try_add_lvalue_reference<T>(0)) {};
template<class T>
struct add_rvalue_reference
: decltype(detail::try_add_rvalue_reference<T>(0)) {};
|
Example
Run this code
#include <type_traits>
using non_ref = int;
static_assert(std::is_lvalue_reference_v<non_ref> == false);
using l_ref = std::add_lvalue_reference_t<non_ref>;
static_assert(std::is_lvalue_reference_v<l_ref> == true);
using r_ref = std::add_rvalue_reference_t<non_ref>;
static_assert(std::is_rvalue_reference_v<r_ref> == true);
using void_ref = std::add_lvalue_reference_t<void>;
static_assert(std::is_reference_v<void_ref> == false);
int main() {}
Defect reports
The following behavior-changing defect reports were applied retroactively to previously published C++ standards.
| DR | Applied to | Behavior as published | Correct behavior |
|---|---|---|---|
| LWG 2101 | C++11 | the program was ill-formed if T is a function type with cv or ref
|
the type produced is T in this case
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See also
(C++11) |
checks if a type is either an lvalue reference or rvalue reference (class template) |
(C++11) |
removes a reference from the given type (class template) |
(C++20) |
combines std::remove_cv and std::remove_reference (class template) |