std::ranges::elements_of
From cppreference.com
| Defined in header <ranges>
|
||
template< ranges::range R, class Allocator = std::allocator<std::byte> > struct elements_of; |
(since C++23) | |
Encapsulates a range. Specializations of elements_of act as a tag in overload sets to disambiguate when a range should be treated as a sequence rather than a single value.
Template parameters
| R | - | a type that satisfies range
|
| Allocator | - | an allocator type that meets the requirements of Allocator |
Data members
| Member name | Definition |
range |
a range of type R (public member object) |
allocator |
an allocator of type Allocator. It has default member initializer that value initializes itself (public member object) |
All these members are declared with [[no_unique_address]] attribute.
Deduction guide
template< class R, class Allocator = std::allocator<std::byte> > elements_of( R&&, Allocator = Allocator() ) -> elements_of<R&&, Allocator>; |
(since C++23) | |
Example
Run this code
#include <any>
#include <generator>
#include <iostream>
#include <ranges>
#include <string_view>
template<bool Elementwise>
std::generator<std::any> gen(std::ranges::input_range auto&& r)
{
if constexpr (Elementwise)
co_yield std::ranges::elements_of(r); // yield each element of r
else
co_yield r; // yield r as a single value
}
int main()
{
auto test = std::string_view{"test"};
for (std::any a : gen<true>(test))
std::cout << '[' << std::any_cast<char>(a) << "] ";
std::cout << '\n';
for (std::any a : gen<false>(test))
std::cout << '[' << std::any_cast<std::string_view>(a) << "] ";
std::cout << '\n';
}
Output:
[t] [e] [s] [t]
[test]
References
- C++23 standard (ISO/IEC 14882:2024):
- 26.5.6 Class template elements_of [range.elementsof]