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    std::imag(std::complex)

    From cppreference.com
     
    C++
     
    Numerics library
     
    std::complex
     
    Defined in header <complex>
    (1)
    template< class T > T imag( const std::complex<T>& z );
    		 (until C++14)
    template< class T > constexpr T imag( const std::complex<T>& z );
    		 (since C++14)
    Additional overloads (since C++11)
    Defined in header <complex>
    (A)
    float imag( float f ); double imag( double f ); long double imag( long double f );
    		 (until C++14)
    constexpr float imag( float f ); constexpr double imag( double f ); constexpr long double imag( long double f );
    		 (since C++14)
    (until C++23)
    template< class FloatingPoint > FloatingPoint imag( FloatingPoint f );
    		 (since C++23)
    (B)
    template< class Integer > double imag( Integer i );
    		 (until C++14)
    template< class Integer > constexpr double imag( Integer i );
    		 (since C++14)
    1) Returns the imaginary part of the complex number z, i.e. z.imag().
    A,B) Additional overloads are provided for all integer and floating-point types, which are treated as complex numbers with zero imaginary part.
    		 (since C++11)

    Parameters

    z - complex value
    f - floating-point value
    i - integer value

    Return value

    1) The imaginary part of z.
    A) decltype(f){} (zero).
    B) 0.0.

    Notes

    See More

    The additional overloads are not required to be provided exactly as (A,B). They only need to be sufficient to ensure that for their argument num:

    • If num has a standard(until C++23) floating-point type T, then std::imag(num) has the same effect as std::imag(std::complex<T>(num)).
    • Otherwise, if num has an integer type, then std::imag(num) has the same effect as std::imag(std::complex<double>(num)).

    See also

    		 accesses the imaginary part of the complex number
    (public member function) [edit]
    		returns the real part
    (function template) [edit]
    C documentation for cimag