std::move_iterator<Iter>::base
From cppreference.com
| (1) | ||
iterator_type base() const; |
(constexpr since C++17) (until C++20) |
|
constexpr const iterator_type& base() const& noexcept; |
(since C++20) | |
constexpr iterator_type base() &&; |
(2) | (since C++20) |
Returns the underlying iterator.
1) Returns a copy of(until C++20)reference to(since C++20) the underlying iterator.
2) Returns an iterator move constructed from the underlying iterator.
Return value
1)
current2)
std::move(current )Example
Run this code
#include <algorithm>
#include <iostream>
#include <iterator>
#include <vector>
int main()
{
std::vector<int> v{0, 1, 2, 3, 4};
std::move_iterator<std::vector<int>::reverse_iterator>
m1{v.rbegin()},
m2{v.rend()};
std::copy(m1.base(), m2.base(), std::ostream_iterator<int>(std::cout, " "));
std::cout << '\n';
}
Output:
4 3 2 1 0
Defect reports
The following behavior-changing defect reports were applied retroactively to previously published C++ standards.
| DR | Applied to | Behavior as published | Correct behavior |
|---|---|---|---|
| LWG 3391 | C++20 | overload (1) returned a copy of the underlying iterator | returns a reference |
| LWG 3593 | C++20 | overload (1) was not noexcept | made noexcept |
See also
| accesses the pointed-to element (public member function) |