std::common_reference_with
From cppreference.com
| Defined in header <concepts>
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template< class T, class U >
concept common_reference_with =
std::same_as<std::common_reference_t<T, U>, std::common_reference_t<U, T>> &&
std::convertible_to<T, std::common_reference_t<T, U>> &&
std::convertible_to<U, std::common_reference_t<T, U>>;
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(since C++20) | |
The concept common_reference_with<T, U> specifies that two types T and U share a common reference type (as computed by std::common_reference_t) to which both can be converted.
Semantic requirements
T and U model std::common_reference_with<T, U> only if, given equality-preserving expressions t1, t2, u1 and u2 such that decltype((t1)) and decltype((t2)) are both T and decltype((u1)) and decltype((u2)) are both U,
std::common_reference_t<T, U>(t1)equalsstd::common_reference_t<T, U>(t2)if and only ift1equalst2; andstd::common_reference_t<T, U>(u1)equalsstd::common_reference_t<T, U>(u2)if and only ifu1equalsu2.
In other words, the conversion to the common reference type must preserve equality.
References
- C++23 standard (ISO/IEC 14882:2024):
- 18.4.5 Concept
common_reference_with[concept.commonref]
- 18.4.5 Concept
- C++20 standard (ISO/IEC 14882:2020):
- 18.4.5 Concept
common_reference_with[concept.commonref]
- 18.4.5 Concept
See also
| determines the common reference type of a group of types (class template) | |
(C++20) |
specifies that two types share a common type (concept) |
(C++11) |
determines the common type of a group of types (class template) |