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std::is_permutation

From cppreference.com
 
 
Algorithm library
Constrained algorithms and algorithms on ranges (C++20)
Constrained algorithms, e.g. ranges::copy, ranges::sort, ...
Non-modifying sequence operations    
Batch operations
(C++17)
Search operations
Modifying sequence operations
Copy operations
(C++11)
(C++11)
Swap operations
Transformation operations
Generation operations
Removing operations
Order-changing operations
(until C++17)(C++11)
(C++20)(C++20)
Sampling operations
(C++17)

Sorting and related operations
Partitioning operations
(C++11)    

Sorting operations
Binary search operations
(on partitioned ranges)
Set operations (on sorted ranges)
Merge operations (on sorted ranges)
Heap operations
Minimum/maximum operations
(C++11)
(C++17)
Lexicographical comparison operations
Permutation operations


 
Defined in header <algorithm>
template< class ForwardIt1, class ForwardIt2 >
bool is_permutation( ForwardIt1 first1, ForwardIt1 last1,
                     ForwardIt2 first2 );
(1) (since C++11)
(constexpr since C++20)
template< class ForwardIt1, class ForwardIt2,
          class BinaryPredicate >
bool is_permutation( ForwardIt1 first1, ForwardIt1 last1,
                     ForwardIt2 first2, BinaryPredicate p );
(2) (since C++11)
(constexpr since C++20)
template< class ForwardIt1, class ForwardIt2 >
bool is_permutation( ForwardIt1 first1, ForwardIt1 last1,
                     ForwardIt2 first2, ForwardIt2 last2 );
(3) (since C++14)
(constexpr since C++20)
template< class ForwardIt1, class ForwardIt2,
          class BinaryPredicate >
bool is_permutation( ForwardIt1 first1, ForwardIt1 last1,
                     ForwardIt2 first2, ForwardIt2 last2,
                     BinaryPredicate p );
(4) (since C++14)
(constexpr since C++20)

Checks whether the first target range [first1, last1) is a permutation of the second target range [first2, last2). For overloads without the last2 parameter, last2 is std::next(first2, std::distance(first1, last1)).

1,3) Elements are compared using operator==.
2,4) Elements are compared using the given binary predicate p.

If ForwardIt1 and ForwardIt2 have different value types, the program is ill-formed.

If the comparator is not an equivalence relation, the behavior is undefined.

Parameters

first1, last1 - the pair of iterators defining the first target range
first2, last2 - the pair of iterators defining the second target range
p - binary predicate which returns ​true if the elements should be treated as equal.

The signature of the predicate function should be equivalent to the following:

bool pred(const Type1 &a, const Type2 &b);

While the signature does not need to have const &, the function must not modify the objects passed to it and must be able to accept all values of type (possibly const) Type1 and Type2 regardless of value category (thus, Type1 & is not allowed, nor is Type1 unless for Type1 a move is equivalent to a copy(since C++11)).
The types Type1 and Type2 must be such that objects of types InputIt1 and InputIt2 can be dereferenced and then implicitly converted to Type1 and Type2 respectively. ​

Type requirements
-
ForwardIt1, ForwardIt2 must meet the requirements of LegacyForwardIterator.

Return value

true if the first target range is a permutation of the second target range, false otherwise.

Complexity

Given N as std::distance(first1, last1):

1,3) 𝓞(N2) comparisons using operator== (or only exactly N comparisons if the two target ranges are lexicographically equal).
2,4) 𝓞(N2) applications of the predicate p (or only exactly N applications if the two target ranges are lexicographically equal).

If both ForwardIt1 and ForwardIt2 meet the requirements of LegacyRandomAccessIterator, and N does not equal std::distance(first2, last2), then no comparison will be made.

Note

std::is_permutation can be used in testing, namely to check the correctness of rearranging algorithms (e.g. sorting, shuffling, partitioning). If x is an original range and y is a permuted range then std::is_permutation(x, y) == true means that y consist of the same elements, maybe staying at other positions.

Possible implementation

template<class ForwardIt1, class ForwardIt2>
bool is_permutation(ForwardIt1 first, ForwardIt1 last, ForwardIt2 d_first)
{
    // skip common prefix
    std::tie(first, d_first) = std::mismatch(first, last, d_first);
    
    // iterate over the rest, counting how many times each element
    // from [first, last) appears in [d_first, d_last)
    if (first != last)
    {
        ForwardIt2 d_last = std::next(d_first, std::distance(first, last));
        for (ForwardIt1 i = first; i != last; ++i)
        {
            if (i != std::find(first, i, *i))
                continue; // this *i has been checked
            
            auto m = std::count(d_first, d_last, *i);
            if (m == 0 || std::count(i, last, *i) != m)
                return false;
        }
    }
    return true;
}

Example

#include <algorithm>
#include <initializer_list>
#include <print>

int main()
{
    static constexpr auto v1 = {1, 2, 3, 4, 5},
                          v2 = {3, 5, 4, 1, 2},
                          v3 = {3, 5, 4, 1, 1};

    for (std::print("{} <- reference list\n", v1); const auto& v : {v2, v3})
        std::print("{} <- is permutation: {}\n", v,
                   std::is_permutation(v1.begin(), v1.end(), v.begin()));
}

Output:

[1, 2, 3, 4, 5] <- reference list
[3, 5, 4, 1, 2] <- is permutation: true
[3, 5, 4, 1, 1] <- is permutation: false

See also

determines if a sequence is a permutation of another sequence
(algorithm function object)[edit]
generates the next greater lexicographic permutation of a range of elements
(function template & algorithm function object)[edit]
generates the next smaller lexicographic permutation of a range of elements
(function template & algorithm function object)[edit]
specifies that a relation imposes an equivalence relation
(concept) [edit]