std::search
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<metanoindex/>
<tbody> </tbody>| Definido no cabeçalho <algorithm>
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template< class ForwardIt1, class ForwardIt2 > ForwardIt1 search( ForwardIt1 first, ForwardIt1 last, ForwardIt2 s_first, ForwardIt2 s_last ); |
(1) | |
template< class ForwardIt1, class ForwardIt2, class BinaryPredicate > ForwardIt1 search( ForwardIt1 first, ForwardIt1 last, ForwardIt2 s_first, ForwardIt2 s_last, BinaryPredicate p ); |
(2) | |
Procura a subseqüência primeiro
[s_first, s_last) elementos no [first, last - (s_last - s_first)) intervalo. A primeira versão utiliza operator== para comparar os elementos, a segunda versão usa o predicado binário dado p.Original:
Searches for the first subsequence of elements
[s_first, s_last) in the range [first, last - (s_last - s_first)). The first version uses operator== to compare the elements, the second version uses the given binary predicate p.The text has been machine-translated via Google Translate.
You can help to correct and verify the translation. Click here for instructions.
You can help to correct and verify the translation. Click here for instructions.
Parâmetros
| first, last | - | a gama de elementos para examinar
Original: the range of elements to examine The text has been machine-translated via Google Translate. You can help to correct and verify the translation. Click here for instructions. |
| s_first, s_last | - | a gama de elementos para pesquisar
Original: the range of elements to search for The text has been machine-translated via Google Translate. You can help to correct and verify the translation. Click here for instructions. |
| p | - | binary predicate which returns true if the elements should be treated as equal. The signature of the predicate function should be equivalent to the following:
The signature does not need to have |
| Type requirements | ||
-ForwardIt1, ForwardIt2 must meet the requirements of ForwardIterator.
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Valor de retorno
Iterator para o início da primeira subsequência
[s_first, s_last) no [first, last - (s_last - s_first)) gama. Se nenhuma subseqüência tal for encontrado, last é returned.Original:
Iterator to the beginning of first subsequence
[s_first, s_last) in the range [first, last - (s_last - s_first)). If no such subsequence is found, last is returned.The text has been machine-translated via Google Translate.
You can help to correct and verify the translation. Click here for instructions.
You can help to correct and verify the translation. Click here for instructions.
Se
[s_first, s_last) está vazio, first é devolvido. (desde C++11)Original:
If
[s_first, s_last) is empty, first is returned. (desde C++11)The text has been machine-translated via Google Translate.
You can help to correct and verify the translation. Click here for instructions.
You can help to correct and verify the translation. Click here for instructions.
Complexidade
Na maioria das comparações dos
S*N onde S = std::distance(s_first, s_last) e N = std::distance(first, last).Original:
At most
S*N comparisons where S = std::distance(s_first, s_last) and N = std::distance(first, last).The text has been machine-translated via Google Translate.
You can help to correct and verify the translation. Click here for instructions.
You can help to correct and verify the translation. Click here for instructions.
Possível implementação
| First version |
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template<class ForwardIt1, class ForwardIt2>
ForwardIt1 search(ForwardIt1 first, ForwardIt1 last,
ForwardIt2 s_first, ForwardIt2 s_last)
{
for (; ; ++first) {
ForwardIt1 it = first;
for (ForwardIt2 s_it = s_first; ; ++it, ++s_it) {
if (s_it == s_last) {
return first;
}
if (it == last) {
return last;
}
if (!(*it == *s_it)) {
break;
}
}
}
}
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| Second version |
template<class ForwardIt1, class ForwardIt2, class BinaryPredicate>
ForwardIt1 search(ForwardIt1 first, ForwardIt1 last,
ForwardIt2 s_first, ForwardIt2 s_last,
BinaryPredicate p)
{
for (; ; ++first) {
ForwardIt1 it = first;
for (ForwardIt2 s_it = s_first; ; ++it, ++s_it) {
if (s_it == s_last) {
return first;
}
if (it == last) {
return last;
}
if (!p(*it, *s_it)) {
break;
}
}
}
}
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Exemplo
| Esta seção está incompleta |
Veja também
encontra a última sequência de elementos em um determinado intervalo Original: finds the last sequence of elements in a certain range The text has been machine-translated via Google Translate. You can help to correct and verify the translation. Click here for instructions. (modelo de função) | |
determina se dois conjuntos de elementos são os mesmos Original: determines if two sets of elements are the same The text has been machine-translated via Google Translate. You can help to correct and verify the translation. Click here for instructions. (modelo de função) | |
(C++11) |
encontra o primeiro elemento satisfazer critérios específicos Original: finds the first element satisfying specific criteria The text has been machine-translated via Google Translate. You can help to correct and verify the translation. Click here for instructions. (modelo de função) |
retorna true se um intervalo é lexicograficamente menor do que outro Original: returns true if one range is lexicographically less than another The text has been machine-translated via Google Translate. You can help to correct and verify the translation. Click here for instructions. (modelo de função) | |
encontra a primeira posição em que dois intervalos diferentes Original: finds the first position where two ranges differ The text has been machine-translated via Google Translate. You can help to correct and verify the translation. Click here for instructions. (modelo de função) | |
Procura por um número de cópias consecutivos de um elemento em uma faixa Original: searches for a number consecutive copies of an element in a range The text has been machine-translated via Google Translate. You can help to correct and verify the translation. Click here for instructions. (modelo de função) | |