std::set_intersection
Da cppreference.com.
|
|
Questa pagina è stata tradotta in modo automatico dalla versione in ineglese della wiki usando Google Translate.
La traduzione potrebbe contenere errori e termini strani. Muovi il puntatore sopra al testo per vedere la versione originale. Puoi aiutarci a correggere gli gli errori. Per ulteriori istruzioni clicca qui. |
<metanoindex/>
<tbody> </tbody>| Elemento definito nell'header <algorithm>
|
||
template< class InputIt1, class InputIt2, class OutputIt > OutputIt set_intersection( InputIt1 first1, InputIt1 last1, InputIt2 first2, InputIt2 last2, OutputIt d_first ); |
(1) | |
template< class InputIt1, class InputIt2, class OutputIt, class Compare > OutputIt set_intersection( InputIt1 first1, InputIt1 last1, InputIt2 first2, InputIt2 last2, OutputIt d_first, Compare comp ); |
(2) | |
Costruisce un inizio gamma smistati
d_first costituito da elementi che si trovano in entrambe le gamme filtrate [first1, last1) e [first2, last2). La prima versione si aspetta che sia l'ingresso che varia da ordinare con operator<, la seconda versione si aspetta che essere ordinati con il confronto comp data funzione. Se qualche elemento si trova m volte in [first1, last1) e n volte [first2, last2), gli elementi std::min(m, n) primo verranno copiati dalla prima serie alla gamma di destinazione. L'ordine degli elementi equivalenti è conservato. L'intervallo risultante non possono sovrapporsi uno dei campi di ingresso.Original:
Constructs a sorted range beginning at
d_first consisting of elements that are found in both sorted ranges [first1, last1) and [first2, last2). The first version expects both input ranges to be sorted with operator<, the second version expects them to be sorted with the given comparison function comp. If some element is found m times in [first1, last1) and n times in [first2, last2), the first std::min(m, n) elements will be copied from the first range to the destination range. The order of equivalent elements is preserved. The resulting range cannot overlap with either of the input ranges.The text has been machine-translated via Google Translate.
You can help to correct and verify the translation. Click here for instructions.
You can help to correct and verify the translation. Click here for instructions.
Parametri
| first1, last1 | - | la prima gamma di elementi da esaminare
Original: the first range of elements to examine The text has been machine-translated via Google Translate. You can help to correct and verify the translation. Click here for instructions. |
| first2, last2 | - | il secondo intervallo di elementi da esaminare
Original: the second range of elements to examine The text has been machine-translated via Google Translate. You can help to correct and verify the translation. Click here for instructions. |
| comp | - | comparison function which returns true if the first argument is less than the second. The signature of the comparison function should be equivalent to the following:
The signature does not need to have |
| Type requirements | ||
-InputIt1 must meet the requirements of InputIterator.
| ||
-InputIt2 must meet the requirements of InputIterator.
| ||
-OutputIt must meet the requirements of OutputIterator.
| ||
Valore di ritorno
Iterator oltre la fine della gamma costruito.
Original:
Iterator past the end of the constructed range.
The text has been machine-translated via Google Translate.
You can help to correct and verify the translation. Click here for instructions.
You can help to correct and verify the translation. Click here for instructions.
Complessità
A confronto la maggior parte 2·(N1+N2-1), dove N1
= std::distance(first1, last1) e N2 = std::distance(first2, last2).Original:
At most 2·(N1+N2-1) comparisons, where N1
= std::distance(first1, last1) and N2 = std::distance(first2, last2).The text has been machine-translated via Google Translate.
You can help to correct and verify the translation. Click here for instructions.
You can help to correct and verify the translation. Click here for instructions.
Possibile implementazione
| First version |
|---|
template<class InputIt1, class InputIt2, class OutputIt>
OutputIt set_intersection(InputIt1 first1, InputIt1 last1,
InputIt2 first2, InputIt2 last2,
OutputIt d_first)
{
while (first1 != last1 && first2 != last2) {
if (*first1 < *first2) {
++first1;
} else {
if (!(*first2 < *first1)) {
*d_first++ = *first1++;
}
++first2;
}
}
return d_first;
}
|
| Second version |
template<class InputIt1, class InputIt2,
class OutputIt, class Compare>
OutputIt set_intersection(InputIt1 first1, InputIt1 last1,
InputIt2 first2, InputIt2 last2,
OutputIt d_first, Compare comp)
{
while (first1 != last1 && first2 != last2) {
if (comp(*first1, *first2)) {
++first1;
} else {
if (!comp(*first2, *first1)) {
*d_first++ = *first1++;
}
++first2;
}
}
return d_first;
}
|
Esempio
#include <iostream>
#include <vector>
#include <algorithm>
#include <iterator>
int main()
{
std::vector<int> v1{1,2,3,4,5,6,7,8};
std::vector<int> v2{ 5, 7, 9,10};
std::sort(v1.begin(), v1.end());
std::sort(v2.begin(), v2.end());
std::vector<int> v_intersection;
std::set_intersection(v1.begin(), v1.end(),
v2.begin(), v2.end(),
std::back_inserter(v_intersection));
for(int n : v_intersection)
std::cout << n << ' ';
}
Output:
5 7
Vedi anche
| computes the union of two sets (funzione di modello) | |