std::move
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<metanoindex/>
<tbody> </tbody>| Déclaré dans l'en-tête <algorithm>
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template< class InputIt, class OutputIt > OutputIt move( InputIt first, InputIt last, OutputIt d_first ); |
(depuis C++11) | |
[first, last) gamme, à un autre début de la plage à d_first. Après cette opération, les éléments de la gamme déplacé-de contiendront toujours des valeurs valides du type approprié, mais pas nécessairement les mêmes valeurs que avant le déménagement .[first, last), to another range beginning at d_first. After this operation the elements in the moved-from range will still contain valid values of the appropriate type, but not necessarily the same values as before the move.You can help to correct and verify the translation. Click here for instructions.
Paramètres
| first, last | - | la plage d'éléments à déplacer
Original: the range of elements to move The text has been machine-translated via Google Translate. You can help to correct and verify the translation. Click here for instructions. |
| d_first | - | le début de la plage de destination. Si
d_first est dans [first, last), std::move_backward doit être utilisé à la place de NJ std :: move </ span> . Original: the beginning of the destination range. If d_first is within [first, last), std::move_backward must be used instead of NJ std :: move </ span>. The text has been machine-translated via Google Translate. You can help to correct and verify the translation. Click here for instructions. |
| Type requirements | ||
-InputIt must meet the requirements of InputIterator.
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-OutputIt must meet the requirements of OutputIterator.
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Retourne la valeur
d_first + (last - first))d_first + (last - first))You can help to correct and verify the translation. Click here for instructions.
Complexité
last - first déplacer les affectations .last - first move assignments.You can help to correct and verify the translation. Click here for instructions.
Mise en œuvre possible
template<class InputIt, class OutputIt>
OutputIt move(InputIt first, InputIt last,
OutputIt d_first)
{
while (first != last) {
*d_first++ = std::move(*first++);
}
return d_first;
}
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Exemple
Le code suivant déplace des objets de fil (qui eux-mêmes sont pas copiables) d'un récipient à un autre. </ p>
The following code moves thread objects (which themselves are not copyable) from one container to another.
You can help to correct and verify the translation. Click here for instructions.
You can help to correct and verify the translation. Click here for instructions.
#include <iostream> #include <vector> #include <list> #include <iterator> #include <thread> #include <chrono> void f(int n) { std::this_thread::sleep_for(std::chrono::seconds(n)); std::cout << "thread " << n << " ended" << '\n'; } int main() { std::vector<std::thread> v; v.emplace_back(f, 1); v.emplace_back(f, 2); v.emplace_back(f, 3); std::list<std::thread> l; // copy() would not compile, because std::thread is noncopyable
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std :: move </ span>(v.begin(), v.end(), std::back_inserter(l)); for(auto& t : l) t.join(); }
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thread 1 ended
thread 2 ended
thread 3 ended
Voir aussi
(C++11) |
se déplace d'une gamme d'éléments vers un nouvel emplacement dans l'ordre inverse Original: moves a range of elements to a new location in backwards order The text has been machine-translated via Google Translate. You can help to correct and verify the translation. Click here for instructions. (fonction générique) |